Last updated: Apr 12, 2024
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The article addresses the following 2 related errors:
The solution to solving the two errors is the same.
The PyTorch "RuntimeError: Input type (torch.FloatTensor) and weight type (torch.cuda.FloatTensor) should be the same" occurs when your model uses the GPU and your data uses the CPU.
To solve the error, use the torch.cuda.is_available()
method to set up and
send your input tensors to the GPU.
import torch # โ Check if cuda is available when calling `device()` device = torch.device( 'cuda:0' if torch.cuda.is_available() else 'cpu' ) for data in dataloader: inputs, labels = data inputs = inputs.to(device) labels = labels.to(device) outputs = model(inputs)
The torch.device() method changes the selected device.
# โ Check if cuda is available when calling `device()` device = torch.device( 'cuda:0' if torch.cuda.is_available() else 'cpu' )
The torch.cuda.is_available() method returns a boolean that indicates if CUDA is currently available.
If the method returns True
, then cuda:0
is returned, otherwise, cpu
is
returned.
The torch.Tensor.to() method is used for moving tensors from CPU to GPU and GPU TO CPU.
for data in dataloader: inputs, labels = data inputs = inputs.to(device) labels = labels.to(device) outputs = model(inputs)
The method can also be used for type conversion.
You can also use the ternary operator to achieve the same result.
import torch device = torch.device( 'cuda' ) if torch.cuda.is_available() else torch.device('cpu') for data in dataloader: inputs, labels = data inputs = inputs.to(device) labels = labels.to(device) outputs = model(inputs)
The torch.device()
method gets called with the string "cuda"
if CUDA is
currently available, otherwise, the method gets called with the string "cpu"
.
cuda()
method to solve the errorYou can also use the cuda()
method to send your input tensors to the GPU.
import torch device = torch.device( 'cuda' ) if torch.cuda.is_available() else torch.device('cpu') print(device) for data in dataloader: inputs, labels = data # ๐๏ธ call cuda() inputs = inputs.cuda() # ๐๏ธ call cuda() labels = labels.cuda() outputs = model(inputs)
The torch.cuda package adds support for CUDA tensor types that implement the same function as CPU tensors but utilize GPUs for computation.
You can also use the is_available()
method to check if your system supports
CUDA as shown in the code sample.
If you want to hardcode the device, use the following code sample instead.
import torch device = torch.device('cuda')
You might also get the error if your input tensors use the GPU, but your model weights don't.
To solve the error in this case, use the is_available()
method to check if
your system supports CUDA and call the cuda()
method on the model.
import torch model = YourModel() if torch.cuda.is_available(): model = model.cuda()
You can also use the model.to()
method to achieve the same result.
import torch model = YourModel() if torch.cuda.is_available(): model.to('cuda') data = data.to('cuda')
If that doesn't work, try to reassign the model
variable to the result of
calling model.to("cuda")
.
model = model.to('cuda')
If you want to hardcode the device, you can also use the following code sample.
import torch device = torch.device('cuda') model = YourModel() model = model.to(device) data = data.to(device)
Alternatively, you can check if the string "cuda"
is present in device
.
import torch device = torch.device( 'cuda' ) if torch.cuda.is_available() else torch.device('cpu') if 'cuda' in device and not torch.cuda.is_available(): device = 'cpu' data = data.to(device) model.to(device)
If the string "cuda"
is present in device
and CUDA is not currently
available, then we set the device
to "cpu"
.
If you get the "RuntimeError: Expected all tensors to be on the same device, but found at least two devices, cuda:0 and cpu" error, make sure that all operations are done on the same device.
You can do this by calling the .to(device)
method on your tensors.
import torch device = torch.device( 'cuda' ) if torch.cuda.is_available() else torch.device('cpu') count0 = torch.zeros(1).to(device) count1 = torch.zeros(1).to(device) count2 = torch.zeros(1).to(device)
Notice that I called .to(device)
on the tensors.
This ensures that all operations are done on the same device.
If the device
variable is not defined, you will likely have to access it as
y.device
or x.device
.
device = y.device # or device = x.device
device
argument when applying transformationsAnother common cause of the error is not setting the device
argument when
applying transformations.
Here is an example of how to correctly set the device
argument.
import torch import torch.nn as nn device = torch.device( 'cuda' ) if torch.cuda.is_available() else torch.device('cpu') # if device is not defined, do x.device or y.device m1 = nn.Linear(20, 100, device=device)
By default, the device
argument is set to None
, so make sure to explicitly
set it.
If the device
variable is not defined, you will likely have to access it as
y.device
or x.device
.
device = y.device # or device = x.device
You can learn more about the related topics by checking out the following tutorials: