Convert a Map object to a List in Python

Convert a Map object to a List in Python #

Use the list() class to convert a map object to a list, e.g. new_list = list(map(my_fuc, my_list)). The list class takes an iterable (such as a map object) as an argument and returns a list object.

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my_list = ['1.1', '2.2', '3.3']

new_list = list(map(float, my_list))

print(new_list)  # 👉️ [1.1, 2.2, 3.3]

print(type(new_list))  # 👉️ <class 'list'>

We passed a map object to the list() class to convert it to a list.

The list class takes an iterable and returns a list object.

The map() function takes a function and an iterable as arguments and calls the function on each item of the iterable.

You can also use the * iterable unpacking operator to convert a map object to a list.

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my_list = ['1.1', '2.2', '3.3']

new_list = [*map(float, my_list)]

print(new_list)  # 👉️ [1.1, 2.2, 3.3]

print(type(new_list))  # 👉️ <class 'list'>

The * iterable unpacking operator enables us to unpack an iterable in function calls, in comprehensions and in generator expressions.

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result = [*(1, 2), *(3, 4), *(5, 6)]

print(result) # 👉️ [1, 2, 3, 4, 5, 6]

An alternative approach would be to directly use a list comprehension.

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my_list = ['1.1', '2.2', '3.3']

new_list = [float(i) for i in my_list]

print(new_list)  # 👉️ [1.1, 2.2, 3.3]

List comprehensions are used to perform some operation for every element, or select a subset of elements that meet a condition.

In the example, we explicitly pass each list item to the float() class instead of doing it implicitly like we did with the map() function.