Solve - ValueError: year is out of range in Python

Solve - ValueError: year is out of range in Python #

The Python "ValueError: year is out of range" occurs when we pass a timestamp that is out of range to the fromtimestamp() method. To solve the error, divide the timestamp by 1000 if it is in milliseconds, e.g. datetime.fromtimestamp(my_ms / 1000).

Here is an example of how the error occurs.

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from datetime import datetime

timestamp_in_ms = 1654618085225

# ⛔️ ValueError: year 54402 is out of range
d = datetime.fromtimestamp(timestamp_in_ms)

The datetime.fromtimestamp() method takes a timestamp in seconds, but we passed it a timestamp in milliseconds which caused the error.

You can convert the milliseconds to seconds by dividing by 1000.

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from datetime import datetime


timestamp_in_ms = 1654618085225

d = datetime.fromtimestamp(timestamp_in_ms / 1000)

print(d)  # 👉️ "2022-06-07 19:08:05.225000"

If you want to preserve the millisecond precision, use float division by dividing by 1000.0 instead.

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from datetime import datetime


timestamp_in_ms = 1654618085225

d = datetime.fromtimestamp(timestamp_in_ms / 1000.0)

print(d)  # 👉️ "2022-06-07 19:08:05.225000"

The datetime.fromtimestamp method takes a timestamp in milliseconds and returns the corresponding local date and time.

If the optional tz argument is not provided, the timestamp is converted to the platform's local date and time.

The method raises ValueError if the timestamp is out of supported values.

You can also use a try/except block to handle the error in a way that suits your use case.

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from datetime import datetime


timestamp_in_ms = 1654618085225

try:
    d = datetime.fromtimestamp(timestamp_in_ms)
except ValueError:
    # 👇️ this runs
    print('except block runs')
    d = datetime.today()

print(d)  # 👉️ "2022-06-07 19:29:06.375292"

We pass the timestamp to the fromtimestamp() method and if a ValueError is raised, the except block is ran where we set the d variable to the current local datetime.