Solve - slice is not a function Error in JavaScript

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Borislav Hadzhiev

Wed Oct 20 20212 min read

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Solve - slice is not a function Error in JavaScript #

The "slice is not a function" error occurs when the slice() method is called on a value that is not of type string or array. To solve the error, convert the value to a string or array before calling the method or make sure to only call the slice method on strings or arrays.

typeerror slice is not a function

Here is an example of how the error occurs.

index.js
const str = 9876; // โ›”๏ธ TypError: slice is not a function const result = str.slice(2);

We called the slice method on a number and got the error. The slice method is implemented on 2 data types in JavaScript - String.slice and Array.slice.

To solve the error, either convert the value to a string or array before calling the method or only call the method if the value is of the correct type.

index.js
// ๐Ÿ‘‡๏ธ For Strings const num = 9876; const result1 = num.toString().slice(2); console.log(result1); // ๐Ÿ‘‰๏ธ "76" // ๐Ÿ‘‡๏ธ For Arrays const set = new Set(['a', 'b', 'c']); const result2 = Array.from(set).slice(2); console.log(result2); // ๐Ÿ‘‰๏ธ ['c']

In the first example, we convert the number to a string using the toString() method before calling the slice method.

In the second example, we used the Array.from method to convert a Set to an array before calling the slice method.

Alternatively, you can conditionally check if the value is of the correct type before calling the slice method.
index.js
const num = 9876; const result1 = typeof num === 'string' ? num.slice(2) : ''; console.log(result1); // ๐Ÿ‘‰๏ธ "" // ๐Ÿ‘‡๏ธ For Arrays const set = new Set(['a', 'b', 'c']); const result2 = Array.isArray(set) ? set.slice(2) : []; console.log(result2); // ๐Ÿ‘‰๏ธ []

In both examples, we used the ternary operator, which is very similar to an if/else statement.

If the expression to the left of the question mark evaluates to a truthy value, the value to the left of the colon is returned, otherwise the value to the right is returned.

In the first example, we check if the value has a type of string. If it does, we return the result of calling the slice method on it, otherwise return an empty string.

In the second example, we check if the value is an array using the Array.isArray method.

If the value is an array, we return the result of calling the slice method on it, otherwise return an empty array.

If the error still persists, console.log the value you're calling theslice method on and make sure it's either of type string or array.

If you have an object, there is a very good chance you have to access a specific property on the object that has a value of an array or string.

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