# Find the Even numbers in an Array using JavaScript Wed Oct 27 20212 min read Photo by Max Vertsanov

## Find the Even Numbers in an Array#

To find the even numbers in an array:

1. Call the `filter()` method, passing it a function.
2. On each iteration, verify that the number doesn't have a remainder when divided by 2.
3. The `filter` method returns a new array containing the elements that satisfy the condition.
index.js
```Copied!```const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9];

const even = arr.filter(number => {
return number % 2 === 0;
});

console.log(even); // 👉️ [2, 4, 6, 8]
``````

The function we passed to the Array.filter method gets called with each element in the array.

If the function returns a truthy value, the element is included in the new array.

On each iteration, we use the modulo (%) operator to check if the number doesn't have a remainder when divided by `2`.

If there is no remainder when the number is divided by `2`, it's an even number.

Only `even` numbers satisfy our condition and will be included in the array that the `filter` method returns.

An alternative approach is to use the Array.forEach method.

To find the even numbers in an array:

1. Create a new array that will store all even numbers.
2. Use the `forEach` method to iterate over the array and verify if each number has a remainder when divided by `2`.
3. If there is no remainder, push the number to the even numbers array.
index.js
```Copied!```const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9];

const even = [];

arr.forEach(number => {
if (number % 2 === 0) {
even.push(number);
}
});

console.log(even); // 👉️ [2, 4, 6, 8]
``````

The function we passed to the `forEach` method gets called with each element in the array.

However, the `forEach` method doesn't return an array like `filter` does.

The `forEach` method returns `undefined`, so we have to create a new array to store the results.

Once the method has iterated over the entire array the `even` array will contain all even numbers from the original array. 