Solve - join is not a function Error in JavaScript

Solve - join is not a function Error #

The "TypeError: join is not a function" occurs when we call the join() method on a value that is not an array. To solve the error, make sure to only call the join method on valid arrays.

Here is an example of how the error occurs.

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const arr = {};

// ⛔️ Uncaught TypeError: join is not a function
const result = arr.join(',');

We called the Array.join() method on an object and got the error back.

To solve the error, console.log the value you're calling the join method on and make sure it's a valid array.

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const arr = ['one', 'two', 'three'];

const result = arr.join(',');

// 👇️ "one,two,three"
console.log(result);

You can conditionally check if the value is an array by using the Array.isArray method.

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const arr = null;

const result = Array.isArray(arr) ? arr.join(',') : "";

console.log(result); // 👉️ ""

We used a ternary operator, which is very similar to an if/else statement.

If the value is an array, we return the result of calling the join method on it, otherwise we return an empty string. This way, you won't get an error, even if the value is not an array.

If you have an array-like object which you're trying to convert to an array before calling the join method, use the Array.from method.

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const set = new Set(['one', 'two', 'three']);

const result = Array.from(set).join(',');
console.log(result); // 👉️ "one,two,three"

Before calling the join method, we convert the value to an array.

You could achieve the same result by using the spread syntax (...).

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const set = new Set(['one', 'two', 'three']);

const result = [...set].join(',');
console.log(result); // 👉️ "one,two,three"