Solve - Cannot read Property 'substring' of Undefined in JS

Solve - Cannot read Property 'substring' of Undefined #

The "Cannot read property 'substring' of undefined" error occurs when calling the substring() method on an undefined value. To solve the error, initialize the value to an empty string or make sure to only call the substring method on strings.

Here is an example of how the error occurs.

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const str = undefined;

// ⛔️ Cannot read properties of undefined (reading 'substring')
str.substring(1);

To solve the error, initialize the value of the variable to an empty string, or make sure to only call the String.substring method on strings.

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const someVar = undefined;

// ✅ Initialize to empty string
const str = someVar || ''; // 👉️ ""

// ✅ Using ternary
const result1 = typeof str === 'string' ? str.substring(1) : '';
console.log(result1); // 👉️ ""

// ✅ Using optional chaining
const result2 = str?.substring(1) || '';
console.log(result2); // 👉️ ""

// ✅ Using if/else
if (typeof str === '') {
  const result3 = str.substring(1);
} else {
  console.log('str is not a string');
}

// ✅ Initialize to empty string
const result4 = (str || '').substring(1);
console.log(result4); // 👉️ ""

We used the logical OR (||) operator to provide a fallback in case the variable stores a falsy value (e.g. undefined).

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const someVar = undefined;

const str = someVar || '';
console.log(str); // 👉️ ""

console.log(str.substring(1)); // 👉️ ""

If the value to the left is falsy, the logical OR (||) operator returns the value to the right.

The next example uses the ternary operator, which is very similar to an if/else statement.

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const str = undefined;

const result1 = typeof str === 'string' ? str.substring(1) : '';
console.log(result1); // 👉️ ""

In other words, if the str variable stores a string, we return the result of calling substring, otherwise we return an empty string.

The next example uses the optional chaining (?.) operator.

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const str = undefined;

const result2 = str?.substring(1) || '';
console.log(result2); // 👉️ ""

The next example uses a simple if/else statement to check if the value is a string before calling the substring() method.

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const str = undefined;

if (typeof str === '') {
  const result3 = str.substring(1);
} else {
  // 👇️ this runs
  console.log('str is not a string');
}

The last example uses the logical OR (||) operator to provide a fallback if the value is falsy.

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const str = undefined;

const result4 = (str || '').substring(1);
console.log(result4); // 👉️ ""

Common reasons the "Cannot read property 'substring' of undefined" error occurs are:

1. Calling the method on a class property that is not initialized to a string
2. Calling the method on an array index that doesn't exist

Here's an example that shows how the error occurs when using arrays.

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const arr = [];

// ⛔️ Cannot read properties of undefined (reading 'substring')
arr[0].substring(1);

To solve the error, make sure the element at the index exists and is of type string.

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const arr = [];

const result = typeof arr?.[0] === 'string' ? arr[0].substring(1) : '';
console.log(result); // 👉️ ""

We check if the array element at the specific index is a string before calling the substring method.

If using classes, make sure to declare the class property and set it to an empty string before accessing it.

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class Person {
  // ✅ Initialize to empty string
  last = '';

  // ✅ Initialize from parameters
  constructor(first) {
    this.first = first;
  }

  substringFirst() {
    return this.first.substring(1);
  }

  substringLast() {
    return this.last.substring(1);
  }
}

const p1 = new Person('John');
p1.substringFirst();
p1.substringLast();

We initialized the values for the first and last class properties. Had we not done that, we would get the error when trying to access the properties.

Conclusion #

The "Cannot read property 'substring' of undefined" error occurs when calling the substring() on an undefined value.

To solve the error, make sure to only call the substring method on strings.