'>' not supported between instances of 'method' and 'int'

'>' not supported between instances of 'method' and 'int' #

The Python "TypeError: '>' not supported between instances of 'method' and 'int'" occurs when we use a comparison operator between a method and an integer. To solve the error, make sure to call the method with parenthesis, e.g. my_method().

Here is an example of how the error occurs.

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class Employee():
    def get_salary(self):
        return 100


emp1 = Employee()

my_int = 10

# ⛔️ TypeError: '>' not supported between instances of 'method' and 'int'
print(emp1.get_salary > my_int) # 👈️ forgot to call method

To solve the error, make sure to call the method.

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class Employee():
    def get_salary(self):
        return 100


emp1 = Employee()

my_int = 10

print(emp1.get_salary() > my_int)  # 👉️ True

We used parenthesis to invoke the method, so now we compare the return value of the method with an integer.

If you aren't sure what type of object a variable stores, use the type() class.

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class Employee():
    def get_salary(self):
        return 100


emp1 = Employee()

print(type(emp1.get_salary))  # 👉️ <class 'method'>
print(callable(emp1.get_salary))  # 👉️ True

my_int = 10

print(type(my_int))  # 👉️ <class 'int'>
print(isinstance(my_int, int))  # 👉️ True

The type class returns the type of an object.

The isinstance function returns True if the passed in object is an instance or a subclass of the passed in class.

The callable function takes an object as an argument and returns True if the object appears callable, otherwise False is returned.

If the callable() function returns True, it is still possible that calling the object fails, however if it returns False, calling the object will never succeed.