Solve - TypeError: list expected at most 1 argument, got 2

Solve - TypeError: list expected at most 1 argument, got 2 #

The Python "TypeError: list expected at most 1 argument, got 2" occurs when we pass multiple arguments to the list() class which takes at most 1 argument. To solve the error, use the range() class to create a range object or pass an iterable to the list() class.

Here is an example of how the error occurs.

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# ⛔️ TypeError: list expected at most 1 argument, got 2
my_list = list(0, 5)

If you meant to create a range of integers, use the range() class.

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my_list = list(range(0, 5))

print(my_list)  # 👉️ [0, 1, 2, 3, 4]

And if you meant to create a list containing multiple items, pass the items in an iterable in the call to the list() class.

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my_list = list(['a', 'b', 'c'])

print(my_list)  # 👉️ ['a', 'b', 'c']

The list class takes an iterable and returns a list object.

The range class is commonly used for looping a specific number of times in for loops and takes the following parameters:

If you only pass a single argument to the range() constructor, it is considered to be the value for the stop parameter.

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for n in range(5):
    print(n)

result = list(range(5))

# 👇️ [0, 1, 2, 3, 4]
print(result)

If values for the start and stop parameters are provided, the start value is inclusive, whereas the stop value is exclusive.

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result = list(range(1, 5))

# 👇️ [1, 2, 3, 4]
print(result)

If the value for the stop parameter is lower than the value for the start parameter, the range will be empty.

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result = list(range(1, 0))

# 👇️ []
print(result)