TypeError: argument of type 'function' is not iterable

TypeError: argument of type 'function' is not iterable #

The Python "TypeError: argument of type 'function' is not iterable" occurs when we use the in or not in operators with a function but forget to call it. To solve the error, make sure to call the function, e.g. my_func().

Here is an example of how the error occurs.

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def get_list():
    return ['a', 'b', 'c']


# ⛔️ TypeError: argument of type 'function' is not iterable
print('a' in get_list) # 👈️ forgot to call function

To solve the error, make sure to call the function.

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def get_list():
    return ['a', 'b', 'c']


print('a' in get_list())  # 👉️ True
print('a' not in get_list())  # 👉️ False

We used parenthesis to invoke the function, so now we check for membership in the list rather than the function.

The in operator tests for membership. For example, x in s evaluates to True if x is a member of s, otherwise it evaluates to False.

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my_str = 'hello world'

print('world' in my_str)  # 👉️ True

print('another' in my_str)  # 👉️ False

x not in s returns the negation of x in s.

All built-in sequences and set types support the in and not in operators.

When used with a dictionary, the operators check for the existence of the specified key in the dict object.