TypeError: 'str' object cannot be interpreted as an integer

TypeError: 'str' object cannot be interpreted as an integer #

The Python "TypeError: 'str' object cannot be interpreted as an integer" occurs when we pass a string to a function that expects an integer argument. To solve the error, pass the string to the int() constructor, e.g. for i in range(int('5')):.

Here is an example of how the error occurs.

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# 👇️ this is a string
my_num = '5'

# ⛔️ TypeError: 'str' object cannot be interpreted as an integer
for i in range(my_num):
    print(i)

We passed a string to the range() constructor which expects an integer argument.

To solve the error, pass the string to the int() constructor to convert it to an integer.

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my_num = '5'

for i in range(int(my_num)):
    print(i)

The error often occurs when getting user input using the built-in input() function.

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# 👇️ this is a string
num = input('Enter your fav number: ')
print(num)
print(type(num))  # 👉️ <class 'str'>

# ⛔️ TypeError: 'str' object cannot be interpreted as an integer
for i in range(num):
    print(i)

The input function converts the data to a string and returns it.

To solve the error, pass the result to the int() constructor.

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num = input('Enter your fav number: ')
print(num)
print(type(num))  # 👉️ <class 'str'>

# ✅ Convert str to integer
for i in range(int(num)):
    print(i)

The int class returns an integer object constructed from the provided number or string argument.

The constructor returns 0 if no arguments are given.

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print(int('10'))  # 👉️ 10
print(int('5'))  # 👉️ 5

The range constructor is commonly used for looping a specific number of times in for loops and takes the following parameters:

If you only pass a single argument to the range() constructor, it is considered to be the value for the stop parameter.

Make sure you aren't declaring a variable that stores an integer initially and overriding it somewhere in your code.

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my_int = 10

# 👇️ reassigned variable to a string by mistake
my_int = '30'

# ⛔️ TypeError: 'str' object cannot be interpreted as an integer
for i in range(my_int):
    print(i)

We initially set the my_int variable to an integer but later reassigned it to a string which caused the error.