# Get the Nth digit of a number in Python Last updated: Sep 23, 2022 Photo from Unsplash

## Get the Nth digit of a number in Python#

To get the Nth digit of a number:

1. Use the `str()` class to convert the number to a string.
2. Access the character at index `N - 1`.
3. Use the `int()` class to convert the result to an integer.
main.py
```Copied!```number = 246810

# ✅ Get Nth digit of a number

second = int(str(number))
print(second)  # 👉️ 4

third = int(str(number))
print(third)  # 👉️ 6

fourth = int(str(number))
print(fourth)  # 👉️ 8

# ------------------------------------

# ✅ Get Nth digit of a number from right to left

second = int(str(number)[-2])
print(second)  # 👉️ 1

third = int(str(number)[-3])
print(third)  # 👉️ 8
``````

We used the `str()` class to convert the integer to a string so we can access the string at a specific index.

Python indexes are zero-based, so the first character in a string has an index of `0`, and the last character has an index of `-1` or `len(my_str) - 1`.

Indexes are zero-based, so we have to access the string at index `N - 1`.

Once we have the Nth digit, we can use the `int()` class to convert the string to an integer.

main.py
```Copied!```number = 246810

second = int(str(number))
print(second)  # 👉️ 4

third = int(str(number))
print(third)  # 👉️ 6
``````

You can use negative indices if you need to get the Nth digit of a number from right to left.

main.py
```Copied!```number = 246810

second = int(str(number)[-2])
print(second)  # 👉️ 1

third = int(str(number)[-3])
print(third)  # 👉️ 8
``````

Negative indices can be used to count backward, e.g. `my_str[-1]` returns the last character in the string and `my_str[-2]` returns the second-to-last character.

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