Solve - flatMap is not a function Error in JavaScript


Borislav Hadzhiev

Wed Oct 20 20212 min read


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Solve - flatMap is not a function Error #

The "flatMap is not a function" error occurs for multiple reasons:

  • Using the flatMap method in a browser that doesn't support it.
  • Using the flatMap method on a value that is not an array.

typeerror flatmap is not a function

Here is an example of how the error occurs.

const arr = {}; // ⛔️ TypeError: arr.flatMap is not a function const result = arr.flatMap(str => str.split(' '));

We called the Array.flatMap() method on an object and got the error back.

To solve the "flatMap is not a function" error, make sure to only call the flatMap method on arrays and in browsers that support it. The flatMap method returns a new array where each element is the result of the callback function flattened to a depth of 1.

const arr = ['one two', 'three four']; const result = arr.flatMap(str => str.split(' ')); // 👇️ ['one', 'two', 'three', 'four'] console.log(result);
The flatMap method is not supported in Internet Explorer. If you have to support the browser, you can use the combination of reduce and concat.
// ✅ Supported in Internet Explorer const arr = ['one two', 'three four']; const result = arr.reduce((acc, curr) => acc.concat(curr.split(' ')), []); // 👇️ ['one', 'two', 'three', 'four'] console.log(result);
However, note that when it comes to large arrays (thousands of values), calling the two functions is a bit slower than using flatMap directly.

You can conditionally check if the value is an array by using the Array.isArray method.

const arr = null; const result = Array.isArray(arr) ? arr.flatMap(str => str.split(' ')) : []; console.log(result); // 👉️ []

We used a ternary operator, which is very similar to an if/else statement.

If the value is an array, we return the result of calling the flatMap method on it, otherwise we return an empty array. This way, you won't get an error, even if the value is not an array.

If the value is fetched from a remote server, make sure it is of the type you expect it to be by logging it to the console and make sure you have parsed it to a native JavaScript array before calling the flatMap method on it.

If you have an array-like object which you're trying to convert to an array before calling the flatMap method, use the Array.from method.

const set = new Set(['one two', 'three four']); const result = Array.from(set).flatMap(str => str.split(' ')); console.log(result); // 👉️ ['one', 'two', 'three', 'four']

Before calling the flatMap method, we convert the value to an array.

You could also use the spread syntax (...) to achieve the same result.

const set = new Set(['one two', 'three four']); const result = [...set].flatMap(str => str.split(' ')); console.log(result); // 👉️ ['one', 'two', 'three', 'four']

If the error persists, console.log the value you're calling the flatMap method on and make sure it's a valid array.

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