Find the Odd Numbers in an Array using JavaScript

Find the Odd Numbers in an Array #

To find the odd numbers in an array:

1. Call the filter() method, passing it a function.
2. On each iteration use the modulo operator to check that the number has a remained when divided by 2.
3. The filter method returns a new array containing the elements that satisfy the condition.

Copied!
const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9];

const odds = arr.filter(number => {
  return number % 2 !== 0;
});

console.log(odds); // 👉️ [1, 3, 5, 7, 9]

The function we passed to the Array.filter method gets called with each element in the array.

On each iteration, we use the modulo (%) operator to check if the number has a remainder when divided by 2.

If there is a remainder, we can conclude that the number is odd.

Only odd numbers satisfy our condition and will be included in the array that the filter method returns.

An alternative approach is to use the Array.forEach method.

To find the odd numbers in an array:

1. Create a new array that will store the odd numbers.
2. Use the forEach method to iterate over the array and on each iteration check that the number has a remainder when divided by 2.
3. If there is a remainder, push the number to the odd numbers array.

Copied!
const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9];

const odds = [];

arr.forEach(number => {
  if (number % 2 !== 0) {
    odds.push(number);
  }
});

console.log(odds); // 👉️ [1, 3, 5, 7, 9]

The function we passed to the forEach method also gets called with each element in the array.

However the forEach method doesn't return an array like filter does.

Once the method has iterated over the entire array the odds variable will contain all odd numbers from the original array.

Further Reading #

• Find the Even numbers in an Array using JavaScript
• Check if String starts with Number using JavaScript